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2(x+12)-3x=2(-x+2)
We move all terms to the left:
2(x+12)-3x-(2(-x+2))=0
We add all the numbers together, and all the variables
2(x+12)-3x-(2(-1x+2))=0
We add all the numbers together, and all the variables
-3x+2(x+12)-(2(-1x+2))=0
We multiply parentheses
-3x+2x-(2(-1x+2))+24=0
We calculate terms in parentheses: -(2(-1x+2)), so:We add all the numbers together, and all the variables
2(-1x+2)
We multiply parentheses
-2x+4
Back to the equation:
-(-2x+4)
-1x-(-2x+4)+24=0
We get rid of parentheses
-1x+2x-4+24=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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