0=b(b-4.5)

Solution for 0=b(b-4.5) equation:

0=b(b-4.5)

We move all terms to the left:

0-(b(b-4.5))=0

We add all the numbers together, and all the variables

-(b(b-4.5))=0


We calculate terms in parentheses: -(b(b-4.5)), so:

b(b-4.5)

We multiply parentheses

b^2-4.5b

Back to the equation:

-(b^2-4.5b)


We get rid of parentheses

-b^2+4.5b=0

We add all the numbers together, and all the variables

-1b^2+4.5b=0

a = -1; b = 4.5; c = 0;
Δ = b2-4ac
Δ = 4.52-4·(-1)·0
Δ = 20.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{20.25}}{2*-1}=\frac{-4.5-\sqrt{20.25}}{-2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{20.25}}{2*-1}=\frac{-4.5+\sqrt{20.25}}{-2}
$