2(2x+3+x-2)=17

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Solution for 2(2x+3+x-2)=17 equation: 



2(2x+3+x-2)=17

We move all terms to the left:

2(2x+3+x-2)-(17)=0

We add all the numbers together, and all the variables

2(3x+1)-17=0

We multiply parentheses

6x+2-17=0

We add all the numbers together, and all the variables

6x-15=0

We move all terms containing x to the left, all other terms to the right

6x=15

x=15/6

x=2+1/2

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