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3(2x-5)-3x(x-7)=2x-9
We move all terms to the left:
3(2x-5)-3x(x-7)-(2x-9)=0
We multiply parentheses
-3x^2+6x+21x-(2x-9)-15=0
We get rid of parentheses
-3x^2+6x+21x-2x+9-15=0
We add all the numbers together, and all the variables
-3x^2+25x-6=0
a = -3; b = 25; c = -6;
Δ = b2-4ac
Δ = 252-4·(-3)·(-6)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{553}}{2*-3}=\frac{-25-\sqrt{553}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{553}}{2*-3}=\frac{-25+\sqrt{553}}{-6} $
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