5(a-4)+7=2(a-5)

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Solution for 5(a-4)+7=2(a-5) equation: 



5(a-4)+7=2(a-5)

We move all terms to the left:

5(a-4)+7-(2(a-5))=0

We multiply parentheses

5a-(2(a-5))-20+7=0



We calculate terms in parentheses: -(2(a-5)), so:

2(a-5)

We multiply parentheses

2a-10

Back to the equation:

-(2a-10)



We add all the numbers together, and all the variables

5a-(2a-10)-13=0

We get rid of parentheses

5a-2a+10-13=0

We add all the numbers together, and all the variables

3a-3=0

We move all terms containing a to the left, all other terms to the right

3a=3

a=3/3

a=1

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