-5(y-2y)+6=-2(4y-y)+9+10y

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Solution for -5(y-2y)+6=-2(4y-y)+9+10y equation: 



-5(y-2y)+6=-2(4y-y)+9+10y

We move all terms to the left:

-5(y-2y)+6-(-2(4y-y)+9+10y)=0

We add all the numbers together, and all the variables

-5(-1y)-(-2(+3y)+9+10y)+6=0

We multiply parentheses

5y-(-2(+3y)+9+10y)+6=0



We calculate terms in parentheses: -(-2(+3y)+9+10y), so:

-2(+3y)+9+10y

determiningTheFunctionDomain
-2(+3y)+10y+9

We add all the numbers together, and all the variables

10y-2(+3y)+9

We multiply parentheses

10y-6y+9

We add all the numbers together, and all the variables

4y+9

Back to the equation:

-(4y+9)



We get rid of parentheses

5y-4y-9+6=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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