3(2x-5)+7x=2(x-5)+1

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Solution for 3(2x-5)+7x=2(x-5)+1 equation: 



3(2x-5)+7x=2(x-5)+1

We move all terms to the left:

3(2x-5)+7x-(2(x-5)+1)=0

We add all the numbers together, and all the variables

7x+3(2x-5)-(2(x-5)+1)=0

We multiply parentheses

7x+6x-(2(x-5)+1)-15=0



We calculate terms in parentheses: -(2(x-5)+1), so:

2(x-5)+1

We multiply parentheses

2x-10+1

We add all the numbers together, and all the variables

2x-9

Back to the equation:

-(2x-9)



We add all the numbers together, and all the variables

13x-(2x-9)-15=0

We get rid of parentheses

13x-2x+9-15=0

We add all the numbers together, and all the variables

11x-6=0

We move all terms containing x to the left, all other terms to the right

11x=6

x=6/11

x=6/11

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