(-3i)(5i)=15

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Solution for (-3i)(5i)=15 equation: 



(-3i)(5i)=15

We move all terms to the left:

(-3i)(5i)-(15)=0

We multiply parentheses

-15i^2-15=0

a = -15; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·(-15)·(-15)
Δ = -900
Delta is less than zero, so there is no solution for the equation

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