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3(2x-4)=-2(3x-+1)
We move all terms to the left:
3(2x-4)-(-2(3x-+1))=0
We add all the numbers together, and all the variables
3(2x-4)-(-2(+3x))=0
We multiply parentheses
6x-(-2(+3x))-12=0
We calculate terms in parentheses: -(-2(+3x)), so:We get rid of parentheses
-2(+3x)
We multiply parentheses
-6x
Back to the equation:
-(-6x)
6x+6x-12=0
We add all the numbers together, and all the variables
12x-12=0
We move all terms containing x to the left, all other terms to the right
12x=12
x=12/12
x=1
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