6z-2(2-z)=4(2z-1)

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Solution for 6z-2(2-z)=4(2z-1) equation: 



6z-2(2-z)=4(2z-1)

We move all terms to the left:

6z-2(2-z)-(4(2z-1))=0

We add all the numbers together, and all the variables

6z-2(-1z+2)-(4(2z-1))=0

We multiply parentheses

6z+2z-(4(2z-1))-4=0



We calculate terms in parentheses: -(4(2z-1)), so:

4(2z-1)

We multiply parentheses

8z-4

Back to the equation:

-(8z-4)



We add all the numbers together, and all the variables

8z-(8z-4)-4=0

We get rid of parentheses

8z-8z+4-4=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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