9(3+x)=6(2x+1)

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Solution for 9(3+x)=6(2x+1) equation: 



9(3+x)=6(2x+1)

We move all terms to the left:

9(3+x)-(6(2x+1))=0

We add all the numbers together, and all the variables

9(x+3)-(6(2x+1))=0

We multiply parentheses

9x-(6(2x+1))+27=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

9x-12x-6+27=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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