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3(2x-4)-1/2(8x+12)=-10
We move all terms to the left:
3(2x-4)-1/2(8x+12)-(-10)=0
Domain of the equation: 2(8x+12)!=0We add all the numbers together, and all the variables
x∈R
3(2x-4)-1/2(8x+12)+10=0
We multiply parentheses
6x-1/2(8x+12)-12+10=0
We multiply all the terms by the denominator
6x*2(8x+12)-12*2(8x+12)+10*2(8x+12)-1=0
Wy multiply elements
12x^2(8-24x(8+20x(8-1=0
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