3(2x-4)+1=(3x-1)-2(x-5)

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Solution for 3(2x-4)+1=(3x-1)-2(x-5) equation: 



3(2x-4)+1=(3x-1)-2(x-5)

We move all terms to the left:

3(2x-4)+1-((3x-1)-2(x-5))=0

We multiply parentheses

6x-((3x-1)-2(x-5))-12+1=0



We calculate terms in parentheses: -((3x-1)-2(x-5)), so:

(3x-1)-2(x-5)

We multiply parentheses

(3x-1)-2x+10

We get rid of parentheses

3x-2x-1+10

We add all the numbers together, and all the variables

x+9

Back to the equation:

-(x+9)



We add all the numbers together, and all the variables

6x-(x+9)-11=0

We get rid of parentheses

6x-x-9-11=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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