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-3(y+3)=y-1+2(3y+4)
We move all terms to the left:
-3(y+3)-(y-1+2(3y+4))=0
We multiply parentheses
-3y-(y-1+2(3y+4))-9=0
We calculate terms in parentheses: -(y-1+2(3y+4)), so:We get rid of parentheses
y-1+2(3y+4)
determiningTheFunctionDomain y+2(3y+4)-1
We multiply parentheses
y+6y+8-1
We add all the numbers together, and all the variables
7y+7
Back to the equation:
-(7y+7)
-3y-7y-7-9=0
We add all the numbers together, and all the variables
-10y-16=0
We move all terms containing y to the left, all other terms to the right
-10y=16
y=16/-10
y=-1+3/5
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