(3)/(2x+9)=(9)/(3x+6)

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Solution for (3)/(2x+9)=(9)/(3x+6) equation: 



(3)/(2x+9)=(9)/(3x+6)

We move all terms to the left:

(3)/(2x+9)-((9)/(3x+6))=0



Domain of the equation: (2x+9)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-9

x!=-9/2

x!=-4+1/2

x∈R





Domain of the equation: (3x+6))!=0

x∈R



We calculate fractions


9x/((2x+9)*(3x+6)))+(-(9*(2x+9))/((2x+9)*(3x+6)))=0



We calculate terms in parentheses: -(9*(2x+9))/((2x+9)*(3x+6))), so:

9*(2x+9))/((2x+9)*(3x+6))

We multiply all the terms by the denominator


9*(2x+9))

We multiply parentheses

18x+

We add all the numbers together, and all the variables

18x

Back to the equation:

-(18x)



We add all the numbers together, and all the variables

-18x+9x/((2x+9)*(3x+6)))+(=0

We multiply all the terms by the denominator


-18x*((2x+9)*(3x+6)))+(+9x=0

We add all the numbers together, and all the variables

9x-18x*((2x+9)*(3x+6)))+(=0

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