3(2x-14)+20=6(3x-5)-28

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Solution for 3(2x-14)+20=6(3x-5)-28 equation: 



3(2x-14)+20=6(3x-5)-28

We move all terms to the left:

3(2x-14)+20-(6(3x-5)-28)=0

We multiply parentheses

6x-(6(3x-5)-28)-42+20=0



We calculate terms in parentheses: -(6(3x-5)-28), so:

6(3x-5)-28

We multiply parentheses

18x-30-28

We add all the numbers together, and all the variables

18x-58

Back to the equation:

-(18x-58)



We add all the numbers together, and all the variables

6x-(18x-58)-22=0

We get rid of parentheses

6x-18x+58-22=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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