3y-8=2(y+1)-4y

Solution for 3y-8=2(y+1)-4y equation:

3y-8=2(y+1)-4y

We move all terms to the left:

3y-8-(2(y+1)-4y)=0


We calculate terms in parentheses: -(2(y+1)-4y), so:

2(y+1)-4y

We add all the numbers together, and all the variables

-4y+2(y+1)

We multiply parentheses

-4y+2y+2

We add all the numbers together, and all the variables

-2y+2

Back to the equation:

-(-2y+2)


We get rid of parentheses

3y+2y-2-8=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2