3(2x+4)=7x+2(3x-8)

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Solution for 3(2x+4)=7x+2(3x-8) equation: 



3(2x+4)=7x+2(3x-8)

We move all terms to the left:

3(2x+4)-(7x+2(3x-8))=0

We multiply parentheses

6x-(7x+2(3x-8))+12=0



We calculate terms in parentheses: -(7x+2(3x-8)), so:

7x+2(3x-8)

We multiply parentheses

7x+6x-16

We add all the numbers together, and all the variables

13x-16

Back to the equation:

-(13x-16)



We get rid of parentheses

6x-13x+16+12=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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