(x+2)(x+5)=3x+x(x-1)

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Solution for (x+2)(x+5)=3x+x(x-1) equation: 



(x+2)(x+5)=3x+x(x-1)

We move all terms to the left:

(x+2)(x+5)-(3x+x(x-1))=0

We multiply parentheses ..

(+x^2+5x+2x+10)-(3x+x(x-1))=0



We calculate terms in parentheses: -(3x+x(x-1)), so:

3x+x(x-1)

We multiply parentheses

x^2+3x-1x

We add all the numbers together, and all the variables

x^2+2x

Back to the equation:

-(x^2+2x)



We get rid of parentheses

x^2-x^2+5x+2x-2x+10=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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