x-(2x+1)=8+(-3x+3)

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Solution for x-(2x+1)=8+(-3x+3) equation: 



x-(2x+1)=8+(-3x+3)

We move all terms to the left:

x-(2x+1)-(8+(-3x+3))=0

We get rid of parentheses

x-2x-(8+(-3x+3))-1=0



We calculate terms in parentheses: -(8+(-3x+3)), so:

8+(-3x+3)

determiningTheFunctionDomain
(-3x+3)+8

We get rid of parentheses

-3x+3+8

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We add all the numbers together, and all the variables

-1x-(-3x+11)-1=0

We get rid of parentheses

-1x+3x-11-1=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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