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3(2x+3)=2(3x+1)+x
We move all terms to the left:
3(2x+3)-(2(3x+1)+x)=0
We multiply parentheses
6x-(2(3x+1)+x)+9=0
We calculate terms in parentheses: -(2(3x+1)+x), so:We get rid of parentheses
2(3x+1)+x
We add all the numbers together, and all the variables
x+2(3x+1)
We multiply parentheses
x+6x+2
We add all the numbers together, and all the variables
7x+2
Back to the equation:
-(7x+2)
6x-7x-2+9=0
We add all the numbers together, and all the variables
-1x+7=0
We move all terms containing x to the left, all other terms to the right
-x=-7
x=-7/-1
x=+7
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