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3(2x+1)=(4x+1)+(2x+1)
We move all terms to the left:
3(2x+1)-((4x+1)+(2x+1))=0
We multiply parentheses
6x-((4x+1)+(2x+1))+3=0
We calculate terms in parentheses: -((4x+1)+(2x+1)), so:We get rid of parentheses
(4x+1)+(2x+1)
We get rid of parentheses
4x+2x+1+1
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
6x-6x-2+3=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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