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3(2x+1)=2(3x+1)+1
We move all terms to the left:
3(2x+1)-(2(3x+1)+1)=0
We multiply parentheses
6x-(2(3x+1)+1)+3=0
We calculate terms in parentheses: -(2(3x+1)+1), so:We get rid of parentheses
2(3x+1)+1
We multiply parentheses
6x+2+1
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
6x-6x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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