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3(2x+1)=3(2x+1)
We move all terms to the left:
3(2x+1)-(3(2x+1))=0
We multiply parentheses
6x-(3(2x+1))+3=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
6x-6x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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