3(2x)=27(2x+5)

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Solution for 3(2x)=27(2x+5) equation:



3(2x)=27(2x+5)
We move all terms to the left:
3(2x)-(27(2x+5))=0
We calculate terms in parentheses: -(27(2x+5)), so:
27(2x+5)
We multiply parentheses
54x+135
Back to the equation:
-(54x+135)
We get rid of parentheses
32x-54x-135=0
We add all the numbers together, and all the variables
-22x-135=0
We move all terms containing x to the left, all other terms to the right
-22x=135
x=135/-22
x=-6+3/22

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