12000/6=6y2/6

Solution for 12000/6=6y2/6 equation:

12000/6=6y^2/6

We move all terms to the left:

12000/6-(6y^2/6)=0

We add all the numbers together, and all the variables

-(6y^2/6)+2000=0

We get rid of parentheses

-6y^2/6+2000=0

We multiply all the terms by the denominator


-6y^2+2000*6=0

We add all the numbers together, and all the variables

-6y^2+12000=0

a = -6; b = 0; c = +12000;
Δ = b2-4ac
Δ = 02-4·(-6)·12000
Δ = 288000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288000}=\sqrt{57600*5}=\sqrt{57600}*\sqrt{5}=240\sqrt{5}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{5}}{2*-6}=\frac{0-240\sqrt{5}}{-12}
=-\frac{240\sqrt{5}}{-12}
=-\frac{20\sqrt{5}}{-1}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{5}}{2*-6}=\frac{0+240\sqrt{5}}{-12}
=\frac{240\sqrt{5}}{-12}
=\frac{20\sqrt{5}}{-1}
$