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10+3(x-5)=-3(x+1)
We move all terms to the left:
10+3(x-5)-(-3(x+1))=0
We multiply parentheses
3x-(-3(x+1))-15+10=0
We calculate terms in parentheses: -(-3(x+1)), so:We add all the numbers together, and all the variables
-3(x+1)
We multiply parentheses
-3x-3
Back to the equation:
-(-3x-3)
3x-(-3x-3)-5=0
We get rid of parentheses
3x+3x+3-5=0
We add all the numbers together, and all the variables
6x-2=0
We move all terms containing x to the left, all other terms to the right
6x=2
x=2/6
x=1/3
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