3(2n+1)=9(6n+2)+6

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Solution for 3(2n+1)=9(6n+2)+6 equation: 



3(2n+1)=9(6n+2)+6

We move all terms to the left:

3(2n+1)-(9(6n+2)+6)=0

We multiply parentheses

6n-(9(6n+2)+6)+3=0



We calculate terms in parentheses: -(9(6n+2)+6), so:

9(6n+2)+6

We multiply parentheses

54n+18+6

We add all the numbers together, and all the variables

54n+24

Back to the equation:

-(54n+24)



We get rid of parentheses

6n-54n-24+3=0

We add all the numbers together, and all the variables

-48n-21=0

We move all terms containing n to the left, all other terms to the right

-48n=21

n=21/-48

n=-7/16

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