19f+20+13f=-20+5(12f-20)

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Solution for 19f+20+13f=-20+5(12f-20) equation: 



19f+20+13f=-20+5(12f-20)

We move all terms to the left:

19f+20+13f-(-20+5(12f-20))=0

We add all the numbers together, and all the variables

32f-(-20+5(12f-20))+20=0



We calculate terms in parentheses: -(-20+5(12f-20)), so:

-20+5(12f-20)

determiningTheFunctionDomain
5(12f-20)-20

We multiply parentheses

60f-100-20

We add all the numbers together, and all the variables

60f-120

Back to the equation:

-(60f-120)



We get rid of parentheses

32f-60f+120+20=0

We add all the numbers together, and all the variables

-28f+140=0

We move all terms containing f to the left, all other terms to the right

-28f=-140

f=-140/-28

f=+5

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