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2(x-3)=4x-(2x+6)
We move all terms to the left:
2(x-3)-(4x-(2x+6))=0
We multiply parentheses
2x-(4x-(2x+6))-6=0
We calculate terms in parentheses: -(4x-(2x+6)), so:We get rid of parentheses
4x-(2x+6)
We get rid of parentheses
4x-2x-6
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
2x-2x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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