3(2m+3)=7(m-3)

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Solution for 3(2m+3)=7(m-3) equation: 



3(2m+3)=7(m-3)

We move all terms to the left:

3(2m+3)-(7(m-3))=0

We multiply parentheses

6m-(7(m-3))+9=0



We calculate terms in parentheses: -(7(m-3)), so:

7(m-3)

We multiply parentheses

7m-21

Back to the equation:

-(7m-21)



We get rid of parentheses

6m-7m+21+9=0

We add all the numbers together, and all the variables

-1m+30=0

We move all terms containing m to the left, all other terms to the right

-m=-30

m=-30/-1

m=+30

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