5(3t-2)=4(2t+1)

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Solution for 5(3t-2)=4(2t+1) equation:



5(3t-2)=4(2t+1)
We move all terms to the left:
5(3t-2)-(4(2t+1))=0
We multiply parentheses
15t-(4(2t+1))-10=0
We calculate terms in parentheses: -(4(2t+1)), so:
4(2t+1)
We multiply parentheses
8t+4
Back to the equation:
-(8t+4)
We get rid of parentheses
15t-8t-4-10=0
We add all the numbers together, and all the variables
7t-14=0
We move all terms containing t to the left, all other terms to the right
7t=14
t=14/7
t=2

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