6(d-2)=2(2d-5)

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Solution for 6(d-2)=2(2d-5) equation: 



6(d-2)=2(2d-5)

We move all terms to the left:

6(d-2)-(2(2d-5))=0

We multiply parentheses

6d-(2(2d-5))-12=0



We calculate terms in parentheses: -(2(2d-5)), so:

2(2d-5)

We multiply parentheses

4d-10

Back to the equation:

-(4d-10)



We get rid of parentheses

6d-4d+10-12=0

We add all the numbers together, and all the variables

2d-2=0

We move all terms containing d to the left, all other terms to the right

2d=2

d=2/2

d=1

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