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3(2c+1)=5c+6
We move all terms to the left:
3(2c+1)-(5c+6)=0
We multiply parentheses
6c-(5c+6)+3=0
We get rid of parentheses
6c-5c-6+3=0
We add all the numbers together, and all the variables
c-3=0
We move all terms containing c to the left, all other terms to the right
c=3
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