2-5(3x-2)=3(x-4)+6

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Solution for 2-5(3x-2)=3(x-4)+6 equation: 



2-5(3x-2)=3(x-4)+6

We move all terms to the left:

2-5(3x-2)-(3(x-4)+6)=0

We multiply parentheses

-15x-(3(x-4)+6)+10+2=0



We calculate terms in parentheses: -(3(x-4)+6), so:

3(x-4)+6

We multiply parentheses

3x-12+6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-15x-(3x-6)+12=0

We get rid of parentheses

-15x-3x+6+12=0

We add all the numbers together, and all the variables

-18x+18=0

We move all terms containing x to the left, all other terms to the right

-18x=-18

x=-18/-18

x=1

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