3x-1+3(3x+1)=-4(x+4)

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Solution for 3x-1+3(3x+1)=-4(x+4) equation: 



3x-1+3(3x+1)=-4(x+4)

We move all terms to the left:

3x-1+3(3x+1)-(-4(x+4))=0

We multiply parentheses

3x+9x-(-4(x+4))+3-1=0



We calculate terms in parentheses: -(-4(x+4)), so:

-4(x+4)

We multiply parentheses

-4x-16

Back to the equation:

-(-4x-16)



We add all the numbers together, and all the variables

12x-(-4x-16)+2=0

We get rid of parentheses

12x+4x+16+2=0

We add all the numbers together, and all the variables

16x+18=0

We move all terms containing x to the left, all other terms to the right

16x=-18

x=-18/16

x=-1+1/8

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