3(2+2q)-4q=-6+3(q+1)

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Solution for 3(2+2q)-4q=-6+3(q+1) equation: 



3(2+2q)-4q=-6+3(q+1)

We move all terms to the left:

3(2+2q)-4q-(-6+3(q+1))=0

We add all the numbers together, and all the variables

3(2q+2)-4q-(-6+3(q+1))=0

We add all the numbers together, and all the variables

-4q+3(2q+2)-(-6+3(q+1))=0

We multiply parentheses

-4q+6q-(-6+3(q+1))+6=0



We calculate terms in parentheses: -(-6+3(q+1)), so:

-6+3(q+1)

determiningTheFunctionDomain
3(q+1)-6

We multiply parentheses

3q+3-6

We add all the numbers together, and all the variables

3q-3

Back to the equation:

-(3q-3)



We add all the numbers together, and all the variables

2q-(3q-3)+6=0

We get rid of parentheses

2q-3q+3+6=0

We add all the numbers together, and all the variables

-1q+9=0

We move all terms containing q to the left, all other terms to the right

-q=-9

q=-9/-1

q=+9

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