-4q-(5q-2)=7+2(2+q)

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Solution for -4q-(5q-2)=7+2(2+q) equation: 



-4q-(5q-2)=7+2(2+q)

We move all terms to the left:

-4q-(5q-2)-(7+2(2+q))=0

We add all the numbers together, and all the variables

-4q-(5q-2)-(7+2(q+2))=0

We get rid of parentheses

-4q-5q-(7+2(q+2))+2=0



We calculate terms in parentheses: -(7+2(q+2)), so:

7+2(q+2)

determiningTheFunctionDomain
2(q+2)+7

We multiply parentheses

2q+4+7

We add all the numbers together, and all the variables

2q+11

Back to the equation:

-(2q+11)



We add all the numbers together, and all the variables

-9q-(2q+11)+2=0

We get rid of parentheses

-9q-2q-11+2=0

We add all the numbers together, and all the variables

-11q-9=0

We move all terms containing q to the left, all other terms to the right

-11q=9

q=9/-11

q=-9/11

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