6+4(z-3)=-3(-5z-2)+2z

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Solution for 6+4(z-3)=-3(-5z-2)+2z equation:



6+4(z-3)=-3(-5z-2)+2z
We move all terms to the left:
6+4(z-3)-(-3(-5z-2)+2z)=0
We multiply parentheses
4z-(-3(-5z-2)+2z)-12+6=0
We calculate terms in parentheses: -(-3(-5z-2)+2z), so:
-3(-5z-2)+2z
We add all the numbers together, and all the variables
2z-3(-5z-2)
We multiply parentheses
2z+15z+6
We add all the numbers together, and all the variables
17z+6
Back to the equation:
-(17z+6)
We add all the numbers together, and all the variables
4z-(17z+6)-6=0
We get rid of parentheses
4z-17z-6-6=0
We add all the numbers together, and all the variables
-13z-12=0
We move all terms containing z to the left, all other terms to the right
-13z=12
z=12/-13
z=-12/13

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