3(1-4a)-2(a+4)=6(a+2)-1

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Solution for 3(1-4a)-2(a+4)=6(a+2)-1 equation: 



3(1-4a)-2(a+4)=6(a+2)-1

We move all terms to the left:

3(1-4a)-2(a+4)-(6(a+2)-1)=0

We add all the numbers together, and all the variables

3(-4a+1)-2(a+4)-(6(a+2)-1)=0

We multiply parentheses

-12a-2a-(6(a+2)-1)+3-8=0



We calculate terms in parentheses: -(6(a+2)-1), so:

6(a+2)-1

We multiply parentheses

6a+12-1

We add all the numbers together, and all the variables

6a+11

Back to the equation:

-(6a+11)



We add all the numbers together, and all the variables

-14a-(6a+11)-5=0

We get rid of parentheses

-14a-6a-11-5=0

We add all the numbers together, and all the variables

-20a-16=0

We move all terms containing a to the left, all other terms to the right

-20a=16

a=16/-20

a=-4/5

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