2(2y-5)=4(2y-3)

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Solution for 2(2y-5)=4(2y-3) equation: 



2(2y-5)=4(2y-3)

We move all terms to the left:

2(2y-5)-(4(2y-3))=0

We multiply parentheses

4y-(4(2y-3))-10=0



We calculate terms in parentheses: -(4(2y-3)), so:

4(2y-3)

We multiply parentheses

8y-12

Back to the equation:

-(8y-12)



We get rid of parentheses

4y-8y+12-10=0

We add all the numbers together, and all the variables

-4y+2=0

We move all terms containing y to the left, all other terms to the right

-4y=-2

y=-2/-4

y=1/2

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