3(y+1)=2(y+4)

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Solution for 3(y+1)=2(y+4) equation: 



3(y+1)=2(y+4)

We move all terms to the left:

3(y+1)-(2(y+4))=0

We multiply parentheses

3y-(2(y+4))+3=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

3y-2y-8+3=0

We add all the numbers together, and all the variables

y-5=0

We move all terms containing y to the left, all other terms to the right

y=5

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