3(-x-5)+8=4(2x+4)+8

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Solution for 3(-x-5)+8=4(2x+4)+8 equation: 



3(-x-5)+8=4(2x+4)+8

We move all terms to the left:

3(-x-5)+8-(4(2x+4)+8)=0

We add all the numbers together, and all the variables

3(-1x-5)-(4(2x+4)+8)+8=0

We multiply parentheses

-3x-(4(2x+4)+8)-15+8=0



We calculate terms in parentheses: -(4(2x+4)+8), so:

4(2x+4)+8

We multiply parentheses

8x+16+8

We add all the numbers together, and all the variables

8x+24

Back to the equation:

-(8x+24)



We add all the numbers together, and all the variables

-3x-(8x+24)-7=0

We get rid of parentheses

-3x-8x-24-7=0

We add all the numbers together, and all the variables

-11x-31=0

We move all terms containing x to the left, all other terms to the right

-11x=31

x=31/-11

x=-2+9/11

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