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3(5x-4)-(4-3x)*5=7x+7(3x-4)
We move all terms to the left:
3(5x-4)-(4-3x)*5-(7x+7(3x-4))=0
We add all the numbers together, and all the variables
3(5x-4)-(-3x+4)*5-(7x+7(3x-4))=0
We multiply parentheses
15x+15x-(7x+7(3x-4))-12-20=0
We calculate terms in parentheses: -(7x+7(3x-4)), so:We add all the numbers together, and all the variables
7x+7(3x-4)
We multiply parentheses
7x+21x-28
We add all the numbers together, and all the variables
28x-28
Back to the equation:
-(28x-28)
30x-(28x-28)-32=0
We get rid of parentheses
30x-28x+28-32=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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