4(x+2)+6=5(x-4)+3

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Solution for 4(x+2)+6=5(x-4)+3 equation: 



4(x+2)+6=5(x-4)+3

We move all terms to the left:

4(x+2)+6-(5(x-4)+3)=0

We multiply parentheses

4x-(5(x-4)+3)+8+6=0



We calculate terms in parentheses: -(5(x-4)+3), so:

5(x-4)+3

We multiply parentheses

5x-20+3

We add all the numbers together, and all the variables

5x-17

Back to the equation:

-(5x-17)



We add all the numbers together, and all the variables

4x-(5x-17)+14=0

We get rid of parentheses

4x-5x+17+14=0

We add all the numbers together, and all the variables

-1x+31=0

We move all terms containing x to the left, all other terms to the right

-x=-31

x=-31/-1

x=+31

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