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2y=5/6y
We move all terms to the left:
2y-(5/6y)=0
Domain of the equation: 6y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
2y-(+5/6y)=0
We get rid of parentheses
2y-5/6y=0
We multiply all the terms by the denominator
2y*6y-5=0
Wy multiply elements
12y^2-5=0
a = 12; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·12·(-5)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*12}=\frac{0-4\sqrt{15}}{24} =-\frac{4\sqrt{15}}{24} =-\frac{\sqrt{15}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*12}=\frac{0+4\sqrt{15}}{24} =\frac{4\sqrt{15}}{24} =\frac{\sqrt{15}}{6} $
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