-5(v+7)(-v+6)=0

Solution for -5(v+7)(-v+6)=0 equation:

-5(v+7)(-v+6)=0

We add all the numbers together, and all the variables

-5(v+7)(-1v+6)=0

We multiply parentheses ..

-5(-1v^2+6v-7v+42)=0

We multiply parentheses

5v^2-30v+35v-210=0

We add all the numbers together, and all the variables

5v^2+5v-210=0

a = 5; b = 5; c = -210;
Δ = b2-4ac
Δ = 52-4·5·(-210)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-65}{2*5}=\frac{-70}{10}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+65}{2*5}=\frac{60}{10}
=6
$