(4l-1)/(l+2)=l

Solution for (4l-1)/(l+2)=l equation:

(4l-1)/(l+2)=l

We move all terms to the left:

(4l-1)/(l+2)-(l)=0


Domain of the equation: (l+2)!=0

We move all terms containing l to the left, all other terms to the right

l!=-2

l∈R


We add all the numbers together, and all the variables

-1l+(4l-1)/(l+2)=0

We multiply all the terms by the denominator


-1l*(l+2)+(4l-1)=0

We multiply parentheses

-l^2-2l+(4l-1)=0

We get rid of parentheses

-l^2-2l+4l-1=0

We add all the numbers together, and all the variables

-1l^2+2l-1=0

a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$l=\frac{-b}{2a}=\frac{-2}{-2}=1$