2y-12+8y=2(5y+4)-20

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Solution for 2y-12+8y=2(5y+4)-20 equation: 



2y-12+8y=2(5y+4)-20

We move all terms to the left:

2y-12+8y-(2(5y+4)-20)=0

We add all the numbers together, and all the variables

10y-(2(5y+4)-20)-12=0



We calculate terms in parentheses: -(2(5y+4)-20), so:

2(5y+4)-20

We multiply parentheses

10y+8-20

We add all the numbers together, and all the variables

10y-12

Back to the equation:

-(10y-12)



We get rid of parentheses

10y-10y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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