1/3(6x-9)=1/2(10+4x)

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Solution for 1/3(6x-9)=1/2(10+4x) equation: 



1/3(6x-9)=1/2(10+4x)

We move all terms to the left:

1/3(6x-9)-(1/2(10+4x))=0



Domain of the equation: 3(6x-9)!=0

x∈R





Domain of the equation: 2(10+4x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(6x-9)-(1/2(4x+10))=0

We calculate fractions


(2x4/(3(6x-9)*2(4x+10)))+(-3x6/(3(6x-9)*2(4x+10)))=0



We calculate terms in parentheses: +(2x4/(3(6x-9)*2(4x+10))), so:

2x4/(3(6x-9)*2(4x+10))

We multiply all the terms by the denominator


2x4

We add all the numbers together, and all the variables

2x^4

We do not support expression: x^4

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